0=-16t^2+50t+16

Solution for 0=-16t^2+50t+16 equation:

0=-16t^2+50t+16

We move all terms to the left:

0-(-16t^2+50t+16)=0

We add all the numbers together, and all the variables

-(-16t^2+50t+16)=0

We get rid of parentheses

16t^2-50t-16=0

a = 16; b = -50; c = -16;
Δ = b2-4ac
Δ = -502-4·16·(-16)
Δ = 3524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3524}=\sqrt{4*881}=\sqrt{4}*\sqrt{881}=2\sqrt{881}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{881}}{2*16}=\frac{50-2\sqrt{881}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{881}}{2*16}=\frac{50+2\sqrt{881}}{32}
$